小型的文本编辑器（使用能通配符*和？）使用时确保你要处理的文件在当前工作目录下。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <conio.h>
typedef struct {
char word[20];
int length;
}wordtype;
wordtype seekword; /*seekword用来放要查找的词*/
wordtype save; /*save用来临时成放从文件中读出的词*/
int check(char ch) /*检查是否是合法的字符*/
{
if(ch<='9'&&ch>='0'||ch<='z'&&ch>='a'||ch<='Z'&&ch>='A')
return 1;
else
return 0;
}
void length() /*计算seekword 和save中的word[]的长度*/
{
int i;
seekword.length=0;
save.length=0;
for(i=0;seekword.word[i]!='\0';i++)
;
seekword.length=i;
for(i=0;save.word[i]!='\0';i++)
;
save.length=i;
}
int compare() /*比较save和seekword中的word[]是否匹配，若匹配返回1，否则返回0* /
{
int length1,length2,i,j,flag1,flag2,breakpoint;
char segment1[20],segment2[20],ch;
if (seekword.length<=save.length){
for(i=0;i<20;i++){
if(seekword.word[i]=='?'||seekword.word[i]=='*'){
ch=seekword.word[i];
breakpoint=i;
}
}
if(ch=='?'||ch=='*'){
for(i=0;i<breakpoint;i++)
segment1[i]=seekword.word[i];
length1=breakpoint;
segment1[i]='\o';
for(j=breakpoint+1,i=0;j<seekword.length;j++,i++)
segment2[i]=seekword.word[j];
segment2[i]='\0';
length2=i;
flag1=flag2=0;
for(i=0;i<length1;i++)
if(segment1[i]!=save.word[i]){
flag1=-1;
break;
}
if(flag1!=-1){
if((breakpoint==seekword.length-1)&&(ch=='?')){
if(save.length==seekword.length)
return 1;
else
return 0;
}
for(i=0,j=save.length-length2;i<length2&&j<save.length;i++,j++)
if(segment2[i]!=save.word[j]){
flag2=-1;
break;
}
}
if(flag1==0&&flag2==0)
return 1;
else
return 0;
}
else{
if(strcmp(save.word,seekword.word)==0)
return 1;
else
return 0;
}
}
else
return 0;